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Language pairs:
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Criteria:
max f(S) / f(T) = 10, max f(T) / f(S) = 10, min f(S) = min f(T) = 5, min p(T|S) = 0.008,
f
1
(S) ∈ [1, 10] → min p(T|S) = 0.3, f
2
(S) ∈ [10, 100] → min p(T|S) = 0.14, f
3
(S) ∈ [100, 1000] → min p(T|S) = 0.04
~
prob
freq
compo
ofwel
0.242
383
hetzij
0.152
205
nu
0.031
2022
namelijk
0.025
394
vaak
0.022
1547
dan
0.015
8430
dit
0.014
7267
zo
0.013
3618
dus
0.011
1859
minimaal
0.010
171
goed
0.010
5133
dan
dit
dus
goed
hetzij
minimaal
namelijk
nu
ofwel
vaak
zo
.